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### Question

If the second half of the following series is reversed, then which item is 4th to the left of the 5th item from the right side? The series is:

C Y U O + @ 7 J 9 X G H 6 % D T F B S I

**A**

Y

**B**

U

**C**

I

**D**

J

**Soln.**

**Ans: c**

Midpoint is 10. We have to find 20 - 5 - 4 = 11 + 1th item from the left side. Since the location lies in the right half, the sequence has been reversed in this zone. So the item will be at location 10 + (20 - 11) = 19 + 1 from the left in the original series. Which means the item is: I.