Discussion of Question with ID = 795 under Alphabet-Number-Series

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Question

If the second half of the following series is reversed, then which item is 3th to the right of the 10th item from the right side? The series is:

6 % P C 4 I 9 B + F H 3 V O @ D 7 W T S

A

+

B

S

C

W

D

T

Soln.
Ans: c

Midpoint is 10. We have to find 20 - 10 + 3 = 13 + 1th item from the left side. Since the location lies in the right half, the sequence has been reversed in this zone. So the item will be at location 10 + (20 - 13) = 17 from the left in the original series. Which means the item is: 7.


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