Three squares have their sides such that they are in an AP(Arithmetic Progression). If the side of the middle square is 8, what is the area of the square whose side is equal to the sum of the sides of these three squares?
576 sq. units.
580 sq. units.
572 sq. units.
584 sq. units.
Let the sides of the three squares be 8 - d, 8 and 8 + d, where d is the common difference. The sum of these is 24, and the area would be $24^2$ = 576 sq. units.