Discussion of Question with ID = 100 under Areas

This is the discussion forum for this question. If you find any mistakes in the solution, or if you have a better solution, then this is the right place to discuss. A healthy discussion helps all of us, so you are requested to be polite and soft, even if you disagree with the views of others. The question and its current solution has also been given on this page.

Advertisement

Question

Three squares have their sides such that they are in an AP(Arithmetic Progression). If the side of the middle square is 19, what is the area of the square whose side is equal to the sum of the sides of these three squares?

A

3249 sq. units.

B

3253 sq. units.

C

3245 sq. units.

D

3257 sq. units.

Soln.
Ans: a

Let the sides of the three squares be 19 - d, 19 and 19 + d, where d is the common difference. The sum of these is 57, and the area would be $57^2$ = 3249 sq. units.


Comments and Discussion