Advertisement

### Question

Three squares have their sides such that they are in an AP(Arithmetic Progression). If the side of the middle square is 19, what is the area of the square whose side is equal to the sum of the sides of these three squares?

**A**

3249 sq. units.

**B**

3253 sq. units.

**C**

3245 sq. units.

**D**

3257 sq. units.

**Soln.**

**Ans: a**

Let the sides of the three squares be 19 - d, 19 and 19 + d, where d is the common difference. The sum of these is 57, and the area would be $57^2$ = 3249 sq. units.