Discussion of Question with ID = 039 under Averages

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Question

Each of the 9 athletes of a Olympics has a timings 88 seconds. If a new athlete with a timings 45 seconds more than the average of all 10 athletes is added, what is the sum total of the values of all 10 athletes?

A

930 seconds.

B

931 seconds.

C

929 seconds.

D

928 seconds.

Soln.
Ans: a

Let the average of all 10 athletes be x, then the required total is T = 10x. By averages, $x = {9 × 88 + (x + 45)}/10$ which is same as $x × 10 = {9 × 88 + (x + 45)}$, which is same as $T = {9 × 88 + (T/10 + 45)}$, solving for T we get 930 seconds.


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