Discussion of Question with ID = 072 under Averages

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Question

The average age of three friends 3 years ago was 33 years. The average age of two them 5 years ago was 19 years. What is the present age of the third friend?

A

60 years.

B

61 years.

C

59 years.

D

58 years.

Soln.
Ans: a

Let the present ages of the three friends be a, b and c. We are given ${(b - 5) + (c - 5)}/2$ = 19. Which gives b + c = 48. We are also given ${(a - 3) + (b - 3) + (c - 3)}/3$ = 33, which gives a + b + c = 3 * 33 + 9 = 108. Putting b + c here we get a = 108 - (b + c) = 108 - 48 = 60 years.


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