The difference of the squares of the downstream and upstream speeds of a boat in a stream is 8. What is the product of the speed of the stream and that of the boat in still water?
Let the speed of the boat in still water be u, and let v be the speed of the stream. The difference of squares of the speeds is $(u + v)^2 - (u - v)^2$, which is $u^2 + v^2 + 2uv - (u^2 + v^2 - 2uv)$ = 4uv = 8. We get uv = $8/4$ = 2.