Discussion of Question with ID = 013 under Distance-and-Time

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Bus X travels 50% faster than bus Y. They start together and meet at the same time after travelling a distance of 30km. What is the speed of the bus X, if the bus Y wasted 5 hours during its journey?


2 kmph.


3 kmph.


5 kmph.


4 kmph.

Ans: a

Let the speed of bus X be x, and of Y be 3x/2. The difference in the times taken by them is $30/x - 30/({3x}/2)$ = 5, which becomes 30 × $1/{3x}$ = 5. Solving, we get x = 2 km/h.

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