Discussion of Question with ID = 022 under HCF-and-LCM

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Question

Which is the second smallest number, which, when divided by 12 and 55, leaves the remainder 5?

A

1325.

B

665.

C

1985.

D

655.

Soln.
Ans: a

The LCM of 12 and 55 = 660. All the numbers that leave remainder 5 upon being divided by either of the given two numbers are of the form 660k + 5. When k = 1, we get the smallest number, and k = 2 gives the next required number = 1325.


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