Discussion of Question with ID = 031 under HCF-and-LCM

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Question

Which is the smallest number, which, when divided by 9 and 65, leaves the remainder 7?

A

592.

B

594.

C

591.

D

595.

Soln.
Ans: a

The LCM of 9 and 65 = 585, is the smallest number, which, when divided by either of them leaves the remainder 0. Now adding, 585 + 7 = 592 is the required number.

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