Discussion of Question with ID = 071 under HCF-and-LCM

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Question

Which is the smallest number, which, when divided by 21 and 80, leaves the remainder 4?

A

1684.

B

1686.

C

1683.

D

1687.

Soln.
Ans: a

The LCM of 21 and 80 = 1680, is the smallest number, which, when divided by either of them leaves the remainder 0. Now adding, 1680 + 4 = 1684 is the required number.

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