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### Question

Which is the smallest number, which, when divided by 21 and 80, leaves the remainder 4?

**A**

1684.

**B**

1686.

**C**

1683.

**D**

1687.

**Soln.**

**Ans: a**

The LCM of 21 and 80 = 1680, is the smallest number, which, when divided by either of them leaves the remainder 0. Now adding, 1680 + 4 = 1684 is the required number.