Discussion of Question with ID = 079 under HCF-and-LCM

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Question

The sum of LCM and HCF of two numbers is 232. If LCM is 57 times the HCF, then the product of the two numbers is?

A

912.

B

914.

C

913.

D

915.

Soln.
Ans: a

Let L be the LCM, and H the HCF. Then H + L = 232, and L = 57H. Solving these for H, we get H = $232/{57 + 1}$ = 4, and L = 228. The product of the two numbers is equal to the product of the lcm and hcf = 4 × 228 = 912.


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