Discussion of Question with ID = 091 under HCF-and-LCM

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Question

Which is the smallest number, which, when divided by 21 and 75, leaves the remainder 3?

A

528.

B

530.

C

527.

D

531.

Soln.
Ans: a

The LCM of 21 and 75 = 525, is the smallest number, which, when divided by either of them leaves the remainder 0. Now adding, 525 + 3 = 528 is the required number.


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