How many words can be formed with 6 distinct consonants and 2 distinct vowels such that vowels stay together at the end of each word?
We have to basically create two parts - one containing 6 consonants and the other containing 2 vowels. The consonants can be arranged in 6 ! ways, and vowels in 2 ! ways. The total count will be 6 ! × 2 ! = 1440.