Discussion of Question with ID = 004 under Pipes-and-Cisterns

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Question

A bucket can be filled by a tap in 6 minutes. Another tap on the same bucket can empty it in 15 mins. How long will it take to fill the bucket if both the taps are opened together?

A

10 mins.

B

11 mins.

C

9 mins.

D

$4{1/3}$ mins.

Soln.
Ans: a

Net part filling in one hour is $1/x - 1/y$ = $(y - x)/(xy)$. So complete filling occurs in $(xy)/(y - x)$ = ${6 × 15}/{15 - 6}$ = 10 mins.


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