Discussion of Question with ID = 019 under Pipes-and-Cisterns

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Two pipes can together fill a cistern in 7 minutes. How long does the slower alone take if the speeds of the pipes are in the ratio 4 : 1?


35 mins.


36 mins.


34 mins.


37 mins.

Ans: a

Let the time taken by the slower pipe alone be x. Then 7 × $(1/x + 4/x)$ = 1. Solving for x, we get x = 7 × 5 = 35 mins.

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