Discussion of Question with ID = 028 under Pipes-and-Cisterns

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Question

Two taps X and Y can fill a tank in 9 and 4 minutes respectively. Both the taps are turned on at the same time. After how many minutes is the tank completely filled?

A

$2{10/13}$ mins.

B

$4{1/12}$ mins.

C

$1{8/15}$ mins.

D

5 mins.

Soln.
Ans: a

Let the time be x mins. Then sum of works done by X and Y = 1. $x/9 + x/4 = 1$. Solving, we get x = $2{10/13}$.


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