Discussion of Question with ID = 035 under Pipes-and-Cisterns

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Two pipes, A and B, can fill a cistern in 11 and 6 mins respectively. There is a leakage tap that can drain 12 liters of water per minute. If all three of them work together, the tank is filled in 6 minutes. What is the volume of the tank?


132 liters.


133 liters.


131 liters.


45 liters.

Ans: a

Work done by the leakage in 1 min is $1/11 + 1/6 - 1/6$ = ${1/11}$. This work is equivalent to a volume of 12 liters. So, the total volume is 12 × 11 = 132 liters.

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