Discussion of Question with ID = 036 under Pipes-and-Cisterns

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Question

A tank is filled in 19 minutes by three taps running together. Tap A is twice as fast as tap B, and tap B is twice as fast as tap C. How much time will tap A take to fill the tank?

A

133 mins.

B

134 mins.

C

132 mins.

D

135 mins.

Soln.
Ans: a

Let the time taken by tap A be x mins. Then 19 minutes work of all the taps should add to 1. So we have, $19 × 1/x + 19 × 2/x + 19 × 4/x$ = 1, which is same as $19 × 7/x$ = 1. Solving, we get x = 133 mins.


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