Discussion of Question with ID = 046 under Pipes-and-Cisterns

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One tap can fill a tank 4 times faster than the other. If they together fill it in 5 minutes, how much time does the slower alone take to fill the tank?


25 mins.


5 mins.


3 mins.


7 mins.

Ans: a

Let the one minute work of the taps be 1/x and 4/x. We have $1/x + 4/x = 1/5$, which gives x = 5 × 5 = 25 mins.

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