Discussion of Question with ID = 066 under Pipes-and-Cisterns

This is the discussion forum for this question. If you find any mistakes in the solution, or if you have a better solution, then this is the right place to discuss. A healthy discussion helps all of us, so you are requested to be polite and soft, even if you disagree with the views of others. The question and its current solution has also been given on this page.

Advertisement

Question

One tap can fill a tank 3 times faster than the other. If they together fill it in 14 minutes, how much time does the slower alone take to fill the tank?

A

56 mins.

B

4 mins.

C

2 mins.

D

6 mins.

Soln.
Ans: a

Let the one minute work of the taps be 1/x and 3/x. We have $1/x + 3/x = 1/14$, which gives x = 4 × 14 = 56 mins.


Comments and Discussion