Discussion of Question with ID = 067 under Pipes-and-Cisterns

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Question

Two taps A and B can fill a tank in 16 and 32 minutes respectively. Both the taps are turned on at the same time. After how many minutes should B be turned off so that the tank can be filled in 12 minutes?

A

8 mins.

B

9 mins.

C

7 mins.

D

11 mins.

Soln.
Ans: a

Let B be closed after x mins. Then sum of works done by A and B = 1. $12/16 + x/32 = 1$. Solving, we get x = 8.

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