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Question
Tap M can fill a cistern in 18 mins. And, a tap N can empty it in 11 mins. In how many minutes will the cistern be emptied if both the taps are opened together when the tank is $13/17$th already empty?
A
$6{78/119}$ mins.
B
$7{85/118}$ mins.
C
$5{68/121}$ mins.
D
$9{60/121}$ mins.
Soln.
Ans: a
Ans: a
1 filled cistern can be emptied in ${18 × 11}/{18 - 11}$ mins. So $1 - 13/17$ = $4/17$ filled cistern can be emptied in ${18 × 11}/{18 - 11}$ × $4/17$ = ${792/119}$, which is same as: $6{78/119}$ mins.