Discussion of Question with ID = 088 under Pipes-and-Cisterns

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Two taps X and Y can fill a tank in 6 and 9 minutes respectively. Both the taps are turned on at the same time. After how many minutes is the tank completely filled?


$3{3/5}$ mins.


$5{3/4}$ mins.


$1{6/7}$ mins.


$4{5/7}$ mins.

Ans: a

Let the time be x mins. Then sum of works done by X and Y = 1. $x/6 + x/9 = 1$. Solving, we get x = $3{3/5}$.

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