Discussion of Question with ID = 095 under Pipes-and-Cisterns

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Two pipes, A and B, can fill a cistern in 11 and 16 mins respectively. There is a leakage tap that can drain 9 liters of water per minute. If all three of them work together, the tank is filled in 17 minutes. What is the volume of the tank?


$95{43/283}$ liters.


$96{139/282}$ liters.


$93{28/57}$ liters.


$97{44/95}$ liters.

Ans: a

Work done by the leakage in 1 min is $1/11 + 1/16 - 1/17$ = ${283/2992}$. This work is equivalent to a volume of 9 liters. So, the total volume is 9 × ${2992/283}$ = ${26928/283}$, which is same as: $95{43/283}$ liters.

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