Discussion of Question with ID = 100 under Pipes-and-Cisterns

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A city tanker is filled by two large pipes, X and Y, together in 24 and 16 minutes respectively. On a certain day, pipe Y is used for first half of the time, and both X and Y are used for the second half. How many minutes does it take to fill the tank?


12 mins.


13 mins.


11 mins.


14 mins.

Ans: a

Let the time taken be x. Y is running for x mins, and X for x/2. So $(x/16 + x/{2 × 24})$ = 1. Solving for x, we get x = 12 mins.

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