Discussion of Question with ID = 022 under Problems-on-Ages

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The ratio of present ages of two monuments A and B is $1{9/11}$. If the difference of their ages is 117, then what is the age of B?


143 years.


132 years.


121 years.


154 years.

Ans: a

The ratio of ages of A and B is given as ${20/11}$, which is same as: $1{9/11}$. So we can write the present ages of A and B, respectively, as 20r and 11r years. The difference is $20r - 11r = 117$ which gives r = 13. The age of B, therefore, is 11r = 11 × 13 = 143 years.

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