Discussion of Question with ID = 026 under Problems-on-Ages

This is the discussion forum for this question. If you find any mistakes in the solution, or if you have a better solution, then this is the right place to discuss. A healthy discussion helps all of us, so you are requested to be polite and soft, even if you disagree with the views of others. The question and its current solution has also been given on this page.



The ratio of present ages of two monuments A and B is $2{9/10}$. After 4 years later the age of A will be 381 years. What is the present age of B?


130 years.


120 years.


110 years.


140 years.

Ans: a

The ratio of ages of A and B is given as ${29/10}$, which is same as: $2{9/10}$. So we can write the present ages of A and B, respectively, as 29r and 10r years. 4 years later the age of A is $29r + 4 = 381$ which gives r = 13. The age of B, therefore, is 10r = 10 × 13 = 130 years.

Comments and Discussion