Discussion of Question with ID = 083 under Problems-on-Ages

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The ratio of present ages of two monuments A and B is $2{1/4}$. After 3 years later the age of A will be 102 years. What is the present age of B?


44 years.


40 years.


36 years.


48 years.

Ans: a

The ratio of ages of A and B is given as ${9/4}$, which is same as: $2{1/4}$. So we can write the present ages of A and B, respectively, as 9r and 4r years. 3 years later the age of A is $9r + 3 = 102$ which gives r = 11. The age of B, therefore, is 4r = 4 × 11 = 44 years.

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