Discussion of Question with ID = 091 under Problems-on-Ages

This is the discussion forum for this question. If you find any mistakes in the solution, or if you have a better solution, then this is the right place to discuss. A healthy discussion helps all of us, so you are requested to be polite and soft, even if you disagree with the views of others. The question and its current solution has also been given on this page.

Advertisement

Question

The ratio of present ages of two monuments A and B is $5{1/4}$. If the difference of their ages is 136, then what is the age of B?

A

32 years.

B

28 years.

C

24 years.

D

36 years.

Soln.
Ans: a

The ratio of ages of A and B is given as ${21/4}$, which is same as: $5{1/4}$. So we can write the present ages of A and B, respectively, as 21r and 4r years. The difference is $21r - 4r = 136$ which gives r = 8. The age of B, therefore, is 4r = 4 × 8 = 32 years.


Comments and Discussion