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### Question

The ratio of present ages of two monuments A and B is $5{1/4}$. If the difference of their ages is 136, then what is the age of B?

**A**

32 years.

**B**

28 years.

**C**

24 years.

**D**

36 years.

**Soln.**

**Ans: a**

The ratio of ages of A and B is given as ${21/4}$, which is same as: $5{1/4}$. So we can write the present ages of A and B, respectively, as 21r and 4r years. The difference is $21r - 4r = 136$ which gives r = 8. The age of B, therefore, is 4r = 4 × 8 = 32 years.