Discussion of Question with ID = 036 under Problems-on-Numbers

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Question

Which term of this arithmetic series is zero: 133, 126, 119 ...?

A

20.

B

21.

C

19.

D

22.

Soln.
Ans: a

The first term is 133, common difference is d = -7, n-th term is 0. So $0 = 133 + (n - 1) × -7$ which gives $n = 1 + {133/7} = 20$.


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