Discussion of Question with ID = 089 under Problems-on-Numbers

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Question

A number is multiplied by 3, then 11 is added to it. The result remains the same if 11 is multiplied to the number and then 101 subtracted. What is the number?

A

14.

B

15.

C

13.

D

16.

Soln.
Ans: a

Let the number be n. From the given conditions we have $3n + 11 = 11n - 101$. Rearranging we have $101 + 11 = 11n - 3n$, ⇒ $n = {101 + 11}/{11 - 3}$. So n = 14.

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