Discussion of Question with ID = 089 under Simple-Interest

This is the discussion forum for this question. If you find any mistakes in the solution, or if you have a better solution, then this is the right place to discuss. A healthy discussion helps all of us, so you are requested to be polite and soft, even if you disagree with the views of others. The question and its current solution has also been given on this page.



A sum of Rs. 1300 is split into two parts. The first part is invested at 12% p.a. and the second at 4% p.a. What is the amount invested at 12% if the total simple interest at the end of 4 years is Rs. 368?


Rs. 500.


Rs. 600.


Rs. 400.


Rs. 700.

Ans: a

Let the amount x be invested at r1% and remaining (P - x) at r2%, and let the sum of interests be I. Then, I = ${x × r_1 × 4}/100$ + ${(P - x) × r_2 × 4}/100$, which simplifies to 100I = 4 × ($x × (r_1 - r_2) + P × r_2$). Putting r1 = 12, r2 = 4, P = 1300, I = 368, we get x = Rs. 500.

Comments and Discussion