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### Question

If x = 0.7727, then what is the value of $4x + √{16x^2 - 8x + 1}$?

**A**

1.

**B**

8.

**C**

16.

**D**

9.

**Soln.**

**Ans: a**

By inspection, $4x + √{16x^2 - 8x + 1}$ is same as $4x + √{({1 - 4x})^2}$, which is same as 4x + (1 - 4x) = 1.