Discussion of Question with ID = 022 under Time-and-Work

This is the discussion forum for this question. If you find any mistakes in the solution, or if you have a better solution, then this is the right place to discuss. A healthy discussion helps all of us, so you are requested to be polite and soft, even if you disagree with the views of others. The question and its current solution has also been given on this page.



A can do a piece of work in 14 days. B is 40% more efficient than A. In how many days can B complete that work?


10 days.


11 days.


9 days.


12 days.

Ans: a

Let us first calculate the one day work of B. One day work of A is given as $1/14$. If B is 40% efficient, then one day work of B is $1/14$ × $140/100$ = $1/10$. Which gives 10 days as the answer.

Comments and Discussion