Discussion of Question with ID = 022 under Time-and-Work

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Question

A can do a piece of work in 14 days. B is 40% more efficient than A. In how many days can B complete that work?

A

10 days.

B

11 days.

C

9 days.

D

12 days.

Soln.
Ans: a

Let us first calculate the one day work of B. One day work of A is given as $1/14$. If B is 40% efficient, then one day work of B is $1/14$ × $140/100$ = $1/10$. Which gives 10 days as the answer.


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