Discussion of Question with ID = 068 under Time-and-Work

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A and B can together complete a job in 49 days. A can alone complete it in 56 days. How long would B alone take to finish the job?


392 days.


393 days.


391 days.


395 days.

Ans: a

One day work of A + B is $1/49$. One day work of A is $1/56$. So one day work of B, say, $1/y$ = $1/49$ - $1/56$. Solving, we get y = 392 days.

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