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### Question

A, B and C complete a work in 11, 16 and 18 days respectively. All three of them start the work together, but A leaves the work after 1 days, and B leaves the work after 6 days. In how many days will the work be completed?

**A**

$9{27/44}$ days.

**B**

$10{27/44}$ days.

**C**

$11{27/44}$ days.

**D**

$12{27/44}$ days.

**Soln.**

**Ans: a**

Use the shortcut formula. If A, B, C can independently complete the job in x, y and z days, and A leaves after n days, and B after m days, the work is completed in z × $(1 - n/x - m/y)$ days. Putting the various values x = 11, y = 16, z = 18, n = 1, m = 6, and simplifying, we get ${423/44}$, which is same as: $9{27/44}$.