Discussion of Question with ID = 097 under Time-and-Work

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A, B and C can independently complete a work in 18, 16 and 6 days respectively. B and C start the work together, but A joins them after 2 days. In how many days will the work be completed?


$3{37/41}$ days.


$4{37/41}$ days.


$5{37/41}$ days.


$6{37/41}$ days.

Ans: a

Use the shortcut formula. If A, B, C can independently complete the job in x, y and z days, and A joins after n days, the work is completed in ${xyz}/{xy + yz + zx}$ × $(1 + n/x)$ days. Putting the various values x = 18, y = 16, z = 6, n = 2, and simplifying, we get ${160/41}$, which is same as: $3{37/41}$.

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