Discussion of Question with ID = 037 under Volume-and-Surface-Areas

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A room has a floor size of 17 × 43 sq. m. What is the height of the room if the sum of the areas of the base and roof is equal to the sum of the areas of the four walls?


$12{11/60}$ m.


$13{24/59}$ m.


$10{51/62}$ m.


$14{43/62}$ m.

Ans: a

Let h be the height, and l and b be the length and breadth. We are given lb + lb = lh + hb + lh + hb. Combining the terms and cancelling 2, we get lb = h(l + b), which gives h = ${lb}/{l + b}$ = ${17 × 43}/{17 + 43}$ = ${731/60}$, which is same as: $12{11/60}$ m.

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